What should be added to xy – 3yz + 4zx to get 4xy – 3zx + 4yz + 7? Solution: The required expression can be got by subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 –.
11/4/2017 · 17. What should be added to xy – 3yz + 4zx to get 4xy – 3zx + 4yz + 7? Solution: By subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx = 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7, The required expression can be got by subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx, The required expression can be got by subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx, Answer: The required expression can be got by subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx) = 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx. = 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7. = 3xy – 7zx + 7yz + 7.
Add : i. 17a²b² + 16c; 28c – 28a²b² ii. 3y² – 10y + 16; 2y – 7 iii. – 3y² + 10y – 16; 7y² + 8 asked Aug 10 in Algebraic Expressions and Operations on them by KomalKumari ( 48.8k points), Find an answer to your question choose for me please, Omar is going on a road trip! the car rental company offers him two types of cars. each car has a fixed price, but he also needs to consider the cost of fuel. the first car costs $90 to rent, and because of its fuel consumption rate, there’s an additional cost of s0.50 per kilometer driven.
